I would like to spend the next few posts talking about a problem I read about in chapter 5 of the book Einstein Manifolds by Arthur Besse (it turns out that the name Arthur Besse is made up as you can read in the preface of the book). The question that we want to address is the following
Given a compact smooth manifold without boundary
, when is it possible to find a Riemannian metric
in
satisfying
for a given Ricci candidate
?
It is of course too ambitious to try to answer this question in full generality but we can start by showing some examples of Ricci candidates for which this equation does not have a solution.
Trying to solve
for
amounts to solving a second order, quasilinear PDE on
, however, the main difficulty here is that the operator
is not elliptic.
A motivation for considering this problem comes from the question of existence of metrics with constant sectional curvature on
– manifolds (compact and without boundary). This of course has to do with the celebrated theorem of Richard Hamilton on the description of
– manifolds with positive Ricci curvature:
Theorem (Hamilton, 1982): Let
be a connected, compact smooth
dimensional manifold without boundary and suppose that
admits a metric
such that
is positive definite everywhere. Then
also admits a metric with constant sectional curvature.
We will discuss some of the ideas involved in the proof of this theorem in future posts. A consequence of this result is that
is diffeomorphic to the quotient of the
-sphere
by a discrete group
.
Back to our original problem, recall that given a Riemannian metric
, the full curvature tensor is defined by

Where
![R(X,Y)Z=\nabla_{X}\nabla_{Y}Z-\nabla_{Y}\nabla_{X}Z-\nabla_{[X,Y]}Z](https://s0.wp.com/latex.php?latex=R%28X%2CY%29Z%3D%5Cnabla_%7BX%7D%5Cnabla_%7BY%7DZ-%5Cnabla_%7BY%7D%5Cnabla_%7BX%7DZ-%5Cnabla_%7B%5BX%2CY%5D%7DZ&bg=ffffff&fg=444444&s=0&c=20201002)
Here
is the Levi-Civita connection of
.
The Ricci tensor is then defined as
.
Here are two basic properties of
:
1)
is symmetric in
and
, i.e. 
2) In local coordinates
looks as follows

We are using the summation convention (i.e we sum over repeated indices). The Christoffel symbols
are defined by

Where
are entries of the matrix
. This says that in local coordinates we can write schematically
where
is a
function that depends linearly on the entries of
. If we then want to solve
locally, property 2) tells us that we have to look at a system of the form

Property 1) tells us that an admissible Ricci candidate
has to be symmetric.
One encounters obstructions for solving this system right away. One of the main difficulties has to do with the fact that the Ricci tensor satisfies the differential Bianchi identity

Where
is the divergence operator respect to
and
is the scalar curvature of
(the trace of the Ricci tensor). This says that if we define a 1-form
by
, then in order for
to satisfy
we must have

To write
in coordinates, we start with

From

(which is just the definition of
in coordinates) and from the expression in local coordinates of the symbols
, we easily see that
![Bian(r,g)_{k}=g^{ij}\left[\partial_{i}r_{jk}-\frac{1}{2}\partial_{k}r_{ij}-g^{ls}r_{ks}\left(\partial_{i}g_{js}-\frac{1}{2}\partial_{s}g_{ij}\right)\right]](https://s0.wp.com/latex.php?latex=Bian%28r%2Cg%29_%7Bk%7D%3Dg%5E%7Bij%7D%5Cleft%5B%5Cpartial_%7Bi%7Dr_%7Bjk%7D-%5Cfrac%7B1%7D%7B2%7D%5Cpartial_%7Bk%7Dr_%7Bij%7D-g%5E%7Bls%7Dr_%7Bks%7D%5Cleft%28%5Cpartial_%7Bi%7Dg_%7Bjs%7D-%5Cfrac%7B1%7D%7B2%7D%5Cpartial_%7Bs%7Dg_%7Bij%7D%5Cright%29%5Cright%5D&bg=ffffff&fg=444444&s=0&c=20201002)
As discussed in Besse’s book, Dennis DeTurck came up with examples of symmetric tensors that cannot satisfy the Bianchi identity respect to any metric. One of his examples is the following
Consider in
a symmetric tensor of the form

The existence of a metric
such that
implies as we saw before that
. In particular, from our expression for
we must have
![0= Bian(r,g)_{1}=g^{ij}\left[\partial_{i}r_{j1}-\frac{1}{2}\partial_{1}r_{ij}-g^{ls}r_{1s}\left(\partial_{i}g_{js}-\frac{1}{2}\partial_{s}g_{ij}\right)\right]=](https://s0.wp.com/latex.php?latex=0%3D+Bian%28r%2Cg%29_%7B1%7D%3Dg%5E%7Bij%7D%5Cleft%5B%5Cpartial_%7Bi%7Dr_%7Bj1%7D-%5Cfrac%7B1%7D%7B2%7D%5Cpartial_%7B1%7Dr_%7Bij%7D-g%5E%7Bls%7Dr_%7B1s%7D%5Cleft%28%5Cpartial_%7Bi%7Dg_%7Bjs%7D-%5Cfrac%7B1%7D%7B2%7D%5Cpartial_%7Bs%7Dg_%7Bij%7D%5Cright%29%5Cright%5D%3D+&bg=ffffff&fg=444444&s=0&c=20201002)

This implies that on the hyperplane
, the metric
must satisfy
which is impossible for a Riemannian metric. It follows that for any point
in the hyperplane
the equation
has no solution near
. Notice that at these points the tensor
is singular.
In the next post we will interpret the existence of examples like the one we have just discussed as a consequence of the non-ellipticity of the system
.